By Dr Antonio Gulli

Bits is the second one of a sequence of 25 Chapters dedicated to algorithms, challenge fixing, and C++ programming. This booklet is set low point bit programming

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**Extra info for A Collection of Bit Programming Interview Questions solved in C++**

**Sample text**

Code unsigned int swapBits(unsigned int x) { unsigned int evenBits = x & 0xAAAAAAAA; unsigned int oddBits = x & 0x55555555; evenBits >>= 1; oddBits <<= 1; return (evenBits | oddBits); } 2. Print the binary representation of an unsigned int Solution An easy solution is to AND the bit with the number Code void bin(unsigned n) { for (unsigned int i = 1 << 31; i > 0; i = i >> 1) if (n & i) std::cout << 1; else std::cout << 0; } 3. Compute whether or not an unsigned number is a power of two Solution Suppose that the number is nonzero.

Size()); ++i) { unsigned int n = i; while (n) { unsigned int bit = n & ~(n - 1); std::cout << set[log2(bit)]; n &= n - 1; } std::cout << ","; } } 23. Add two decimal strings representing two integers Solution The two strings can represent very large integers. The algorithm used for summing the value is the one taught at primary school. resize(len); for (int i = len - 1; i >= 0; i--) { b1 = s1[i] - '0'; b2 = s2[i] - '0'; sum = (b1 + b2 + carry); carry = sum / 10; res[i] = (char)sum % 10 + '0'; } if (carry) res = '1' + res; return res; } 24.

ACKNOWLEDGMENTS Thanks to Antonio Savona for his code review Contents Contents 1. Given an unsigned int, swap the bits in odd and even positions Solution Code 2. Print the binary representation of an unsigned int Solution Code 3. Compute whether or not an unsigned number is a power of two Solution Code 4. Set the i-th bit Solution 5. Unset the i-th bit Solution 6. Toggle the i-th bit Solution 7. Given an unsigned number with only one bit set, find the position of this bit Solution Code Solution Code Solution Code 8.